Question

Show that 12^n cannot end with digits 0 or 5 for any natural number n.

Answer 1

12^n = 2^n×2^n×3^n
For a number to end with 0 . It must have 2 and 5 as its factor. Therefore 12^n cannot end with 0

Answer 2

There is an interesting pattern here. Check 12^1=12
12^2=ends with digit 4
12^3=ends with digit 8
12^4=ends with digit 6
And now this pattern repeats for 12^5,12^6......etc
Thus it cannot have 0 or 5 digit
OR ANOTHER SOLUTION
Factors of 12^n=4^n×3^n
4^n or 3^n cannot end with 0 or 5.
Cheers. Mark brainliest.