Question

show that 12n can never end with the digit zero for any natural number n.​

Answer 1

Answer:

Here, Number 12 n where nϵN

Now 12 n

=(22 ×3) n Now, for 12

n to end with 0, it should have 2 as well as 5 in its prime factors. Also to end with 5, of require at least a single multiple of 5 in its prime factors, so 12 n cannot end with the digit 0 or 5.