Question

show that 12n cannot end with the digit 0 or 5 any natural no. n ( dont write useless ans.)​

Answer 1

Answer:

Here, Number 12

n

where nϵN

Now 12

n

=(2

2

×3)

n

Now, for 12

n

to end with 0, it should have 2 as well as 5 in its prime factors. Also to end with 5, of require at least a single multiple of 5 in its prime factors, so 12

n

cannot end with the digit 0 or 5.

Answer 2

For your question 12n, it can end with 0 and 5

But if the the question is for 12^n then please follow below

$for \: \: {12}^{n} \: to \: end \: with \: 0, \: it \: should \: have \: 2 \: as \: well \: as \: 5 \\ \: in \: its \: prime \: factors.\\ \: Also \: to \: end \: with \: 5, \: of \: require \: at \: least \:\\ a \: single \: multiple \: of \: 5 \: in its \: prime \: factors, \\ \: so {12}^{n} \: cannot \: end \: with \: the \: digit \: 0 \: or \: 5.$