Question

Show that 12n cannot end with the digit 0 or 5 for any natural number.

Answer 1

Step-by-step explanation:

This is the answer of this question

Answer 2

Step-by-step explanation:

${12}^{n}$

let n = 1

12^1 = 12

n=2

12^2 = 144

this gives us the result that n= natural number

then it will always end with multiple of 2

e.g 1, 2, 4 etc