Show that 12n cannot end with the digit 0 or 5 for any natural number n.
NCERT Class X
Mathematics - Exemplar Problems
Chapter _Real Numbers
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12 =2^2 ×3
12n = (2^2×3)n = (2)^ 2n × 3n
So only primes in the factorization of 12n are 2 and 3 and not 5
Hence 12n cannot end with 0 or 5
12n = (2^2×3)n = (2)^ 2n × 3n
So only primes in the factorization of 12n are 2 and 3 and not 5
Hence 12n cannot end with 0 or 5
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