Question

show that 12n cannot end with the digit 0 or 5 for any natural number n.

Answer 1

Answer:

Let if possible 12n for any natural number n ends with 0 or5

it must be divisible by the prime factor 5

But 12n=(2×3×2) n

So 12n has no factor as 5 or 0

Therefore 12n can never end with 0