Question

Show that (13a- 5b) square+260ab = (13a+5b) square

Answer 1

Answer:

${(13a - 5b)}^{2} + 260ab \\ = {(13a)}^{2} + {(5b)}^{2} - 2 \times 13a \times 5b + 260ab \\ = {(13a)}^{2} + {(5b)}^{2} - 130ab + 260ab \\ = {(13a)}^{2} + {(5b)}^{2} + 130ab \\ = {(13a)}^{2} + {(5b)}^{2} + 2 \times 13a \times 5b \\ = {(13a + 5b)}^{2}$

Answer 2

Answer:

this is correct ..........