Show that 13n cannot end with the digit 0 or 5 for any natural number n.
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If any number ends with the digit 0 or 5, it is always divisible by 5. ... This is possible only if prime factorisation of 12n contains the prime number 5. This is possible only if prime factorisation of 12n contains the prime number 5.
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Answer. If any number ends with the digit 0 or 5, it is always divisible by 5. ... This is possible only if prime factorisation of 12n contains the prime number 5. This is possible only if prime factorisation of 12n contains the prime number 5.
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