Question

show that 1728 is a perfect cube​

Answer 1

Answer:

Thus,1728 is a perfect cube.

Hope it will help

Answer 2

Step-by-step explanation:

How to show if a number is a perfect cube?

If it forms triplets of same number.

So, in this case, 1728 can be written as 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 3.

You can see that it has 6 "2s" so it means 2 pairs of 2 and it has 1 "3s" so 1 pair of 3.

So, it'll be the cube of 2 × 2 × 3 = 12