Question

show that (-18)÷[6÷(-1)=[(-18)÷6]÷(-1)​

Answer 1

L.H.S

(-18)÷[-6]

=3

and

R.H.S

=[(-18)÷6]÷(-1)

= (-3)÷(-1)

=3

here L.H.S= R.H.S= 3

hence, L.H.S = R.H.S

follow me.....

Answer 2

Answer:

=> By calculating both sides we get similar values.

Step-by-step explanation:

As per the data given in the question, we have to show that

$(-18)\div[6\div(-1)]=[(-18)\div6]\div(-1)$

By using the method of BODMAS, on both sides:

It is a method of performing various arithmetic operations to solve various expressions.

As we have,

=> $(-18)\div[6\div(-1)]=[(-18)\div6]\div(-1)$

=> $(-18)\div(-6)=(-3)\div(-1)$

=> 3 = 3

LHS = RHS

Hence proved.