Question

show that 18900 is a perfect square​

Answer 1

$step \: 1$

$prime \: factorisation \: of18900$

$step \: 2$

$18900 = 2 \times 2 \times 3 \times 3 \times 5 \times 5 \times 7 \times 3$

$step \: 3$

$we \: observe \: that \: 3and7 \: doesnt \: exist \: in \: pairs \\ therefore \: 18900 \: is \: not \: a \: perfect \: square$

$because \: 7 \: and \: 3 \: does \: not \: exist \: in \: pairs$

Answer 2

It is not a perfect square