Math, asked by dev2774, 1 year ago

Show that 19683 is a perfect cube. Also Find the number whose cube is this number

Answers

Answered by 11Aditi
0
Hey mate,
It is a perfect cube of 27
That means, it's cube root is 27.
And you can find this by long division method.
OK
Hope it helps
Please mark my answer as brainlest answer
Answered by shreeyamukherjee
0

Answer:

27

Step-by-step explanation:

19683 = 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3

√19683 = 3 X 3 X 3 = 27

Hope it helps

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