show that √2+1
Square root2+square root of 2+2 cos 4theta = 2cos (theta/2)
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Answer:
√{2+√(2+2cos4A)}
=√[2+√{2+2(2cos²2A-1)}]
=√{2+√(2+4cos²2A-2)}
=√(2+√4cos²2A)
=√(2+2cos2A)
=√{2+2(2cos²A-1)}
=√(2+4cos²A-2)
=√4cos²A
=2cosA(Proved)
Step-by-step explanation:
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