Question

show that (2,-2),(-3,8),(-1,4)are collinear

Answer 1

hope it helps you mate ;)

Answer 2

Hey dear !!!

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Let, P,Q R are the given points ..

∴ P(2,-2)

Q(-3,8)

R(-1,4)

$slope \: of \: line \: PQ \: = \frac{y2- y1}{x2 - x1}$

$= \frac{8 - ( - 2)}{ - 3 - 2} \\ = \frac{8 + 2}{ - 5} \\ = \frac{10}{ - 5} \\ = - 2$

∴ slope of line PQ = -2

Similarly,

$slope \: of \: line \: QR \: = \frac{y2- y1}{x2 - x1}$


$= \frac{4 - 8}{ - 1 - ( - 3)} \\ = \frac{ - 4}{ - 1 + 3} \\ = \frac{ - 4}{2} \\ = - 2$

∴ slope of line QR = -2

SLOPE OF LINE PQ AND LINE QR IS EQUAL ..

But, point Q lies on both the lines .

∴ Point P,Q,R are collinear .

∴ (2-2) (-3,8) (-1,4) are collinear .

Thanks !!!!