Question

show that 2+3√2/7 is not a rational number given that root 2 is an irrational number​

Answer 1

2+3√2/7

let us assume that 2+3√2/7 is rational no.

so 2+3√2/7=p/q

3√2/7=p–2q/q

√2/7=p–2q/3q

√2=7(p–2q/3q)

irrational no. = rational no.

which is not possible. so 2+3√2/7

is a iraational no.

hence proved

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Answer 2

Answer:

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