Show that 2 + 3√2 is not irrational no given that √2 is an irrational no
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Step-by-step explanation:
let the assume 2 +3√2 is rational no
so, 2 +3√3 in the form of p/q therefore, 2 +3√2 = a/b (where a or b≠0)
= 3√2 = a/b - 2
= 3√2 = (a-2b)/b
= √2 = (a-2b)/3b
but √2 is a irrational no
then, (a-2b)/3b is a irrational no
so, our assumption is wrong
2+3√2 is a irrational no
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