show that 2√3-5 is an irrational number if it is given that √3 is irrational
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Answer:
Let x=2−3
5
be a rational number.
3
5
=2−x
5
=
3
2−x
Since x is rational, 2-x is rational and hence
3
2−x
is also rational number
⇒
5
is a rational numbers, which is a contradiction.
Hence 2−3
5
must be an irrational number
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