Question

Show that √2+√3 is an irrational number . Where √6 is irrational .

Answer 1

Step-by-step explanation:

We can prove it by contradictory method..

We assume that 2 + √3 is a rational number.

=> 2 + √3 = p/q , where p & q are integers, ‘q’ not = 0.

=> √3 = (p/q) - 2

=> √3 = (p - 2q)/ q ………… (1)

=> here, LHS √3 is an irrational number.

But RHS is a rational number.. Reason- the difference of 2 integers is always an integer. So the numerator (p- 2q) is an integer.

& the denominator ‘q’ is an integer.&‘q’ not = 0

This way, all conditions of a rational number are satisfied.

=> RHS (p- 2q)/q is a rational number.

But , LHS is an irrational.

=> LHS of….. (1) is not = RHS.

=> Our assumption, that 2 + √3 is a rational number, is incorrect..

=> 2 + √3 is an irrational number

Hope it helps!!

Answer 2

Step-by-step explanation:

heya here is ur answer maybe it help u