Question

show that √2+√3 is irrational ​

Answer 1

Step-by-step explanation:

Let √2 + √3 = (a/b) is a rational no. On squaring both sides , we get 2 + 3  + 2√6 = (a2/b2) So,5 + 2√6 = (a2/b2) a rational no. So, 2√6 = (a2/b2) – 5 Since, 2√6 is an irrational no. and (a2/b2) – 5 is a rational no. So, my contradiction is wrong. So, (√2 + √3) is an irrational no.

Answer 2

Answer:

$\sqrt{2} + \sqrt{3} = a \\ 2 + 3 + 2 \sqrt{6 } = {a }^{2} \\ \sqrt{6 } = ( {a}^{2} - 6) \frac{1}{2}$

Step-by-step explanation:

so root 6 is irrational but rhs is rational so we can say that th given is irrational....

plz check this one....