Show that (2√5 - 3√2) (2√5 + 3√2) = 2
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asit183:
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here..using the formula,we have
(a-b)(a+b)=a^2 - b^2
now..here...a = 2√5 nd b = 3√2
so....by using the formula...we get,
(2√5)^2 - (3√2)^2 = (4×5) - (9×2)= 20-18=2
i.e., LHS = RHS
(a-b)(a+b)=a^2 - b^2
now..here...a = 2√5 nd b = 3√2
so....by using the formula...we get,
(2√5)^2 - (3√2)^2 = (4×5) - (9×2)= 20-18=2
i.e., LHS = RHS
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