Math, asked by Varadnb230, 7 months ago

Show that (-2/5+4/5)+(-3/4)=-2/5+(4/9+(-3/4))

Answers

Answered by samuelsebastian
0

Step-by-step explanation:

=> (-a + b) + (-c) ≠ a + (b + (-c) )

-___________________

___________________●GIVEN QUESTION :-

___________________●GIVEN QUESTION :- = > ( \frac{ - 2}{5} + \frac{4}{9} ) + \frac{ - 3}{4} = \frac{2}{5} + ( \frac{4}{9} + \frac{ - 3}{4} ) \\ \\ = > ( \frac{( - 2) \times 9 + 4 \times 5}{45}) + \frac{ - 3}{4} = \frac{2}{5} + ( \frac{4 \times 4 + ( - 3) \times 9}{36} ) \\ \\ = > \frac{ - 18 + 20}{45} + \frac{ - 3}{4} = \frac{2}{5} + \frac{16 - 27}{36} \\ \\ = > \frac{ - 2}{45} + \frac{ - 3}{4} = \frac{2}{5} + \frac{ - 11}{36} \\ \\ = > \frac{ - 8 - 135}{180} = \frac{72 - 55}{180} \\ \\ = > - 143 = 17

___________________●GIVEN QUESTION :- = > ( \frac{ - 2}{5} + \frac{4}{9} ) + \frac{ - 3}{4} = \frac{2}{5} + ( \frac{4}{9} + \frac{ - 3}{4} ) \\ \\ = > ( \frac{( - 2) \times 9 + 4 \times 5}{45}) + \frac{ - 3}{4} = \frac{2}{5} + ( \frac{4 \times 4 + ( - 3) \times 9}{36} ) \\ \\ = > \frac{ - 18 + 20}{45} + \frac{ - 3}{4} = \frac{2}{5} + \frac{16 - 27}{36} \\ \\ = > \frac{ - 2}{45} + \frac{ - 3}{4} = \frac{2}{5} + \frac{ - 11}{36} \\ \\ = > \frac{ - 8 - 135}{180} = \frac{72 - 55}{180} \\ \\ = > - 143 = 17________________________________

___________________●GIVEN QUESTION :- = > ( \frac{ - 2}{5} + \frac{4}{9} ) + \frac{ - 3}{4} = \frac{2}{5} + ( \frac{4}{9} + \frac{ - 3}{4} ) \\ \\ = > ( \frac{( - 2) \times 9 + 4 \times 5}{45}) + \frac{ - 3}{4} = \frac{2}{5} + ( \frac{4 \times 4 + ( - 3) \times 9}{36} ) \\ \\ = > \frac{ - 18 + 20}{45} + \frac{ - 3}{4} = \frac{2}{5} + \frac{16 - 27}{36} \\ \\ = > \frac{ - 2}{45} + \frac{ - 3}{4} = \frac{2}{5} + \frac{ - 11}{36} \\ \\ = > \frac{ - 8 - 135}{180} = \frac{72 - 55}{180} \\ \\ = > - 143 = 17________________________________●SO.... WE KNOW THAT :-

___________________●GIVEN QUESTION :- = > ( \frac{ - 2}{5} + \frac{4}{9} ) + \frac{ - 3}{4} = \frac{2}{5} + ( \frac{4}{9} + \frac{ - 3}{4} ) \\ \\ = > ( \frac{( - 2) \times 9 + 4 \times 5}{45}) + \frac{ - 3}{4} = \frac{2}{5} + ( \frac{4 \times 4 + ( - 3) \times 9}{36} ) \\ \\ = > \frac{ - 18 + 20}{45} + \frac{ - 3}{4} = \frac{2}{5} + \frac{16 - 27}{36} \\ \\ = > \frac{ - 2}{45} + \frac{ - 3}{4} = \frac{2}{5} + \frac{ - 11}{36} \\ \\ = > \frac{ - 8 - 135}{180} = \frac{72 - 55}{180} \\ \\ = > - 143 = 17________________________________●SO.... WE KNOW THAT :-●"-143" is never equal to "17"

___________________●GIVEN QUESTION :- = > ( \frac{ - 2}{5} + \frac{4}{9} ) + \frac{ - 3}{4} = \frac{2}{5} + ( \frac{4}{9} + \frac{ - 3}{4} ) \\ \\ = > ( \frac{( - 2) \times 9 + 4 \times 5}{45}) + \frac{ - 3}{4} = \frac{2}{5} + ( \frac{4 \times 4 + ( - 3) \times 9}{36} ) \\ \\ = > \frac{ - 18 + 20}{45} + \frac{ - 3}{4} = \frac{2}{5} + \frac{16 - 27}{36} \\ \\ = > \frac{ - 2}{45} + \frac{ - 3}{4} = \frac{2}{5} + \frac{ - 11}{36} \\ \\ = > \frac{ - 8 - 135}{180} = \frac{72 - 55}{180} \\ \\ = > - 143 = 17________________________________●SO.... WE KNOW THAT :-●"-143" is never equal to "17"●THEN

___________________●GIVEN QUESTION :- = > ( \frac{ - 2}{5} + \frac{4}{9} ) + \frac{ - 3}{4} = \frac{2}{5} + ( \frac{4}{9} + \frac{ - 3}{4} ) \\ \\ = > ( \frac{( - 2) \times 9 + 4 \times 5}{45}) + \frac{ - 3}{4} = \frac{2}{5} + ( \frac{4 \times 4 + ( - 3) \times 9}{36} ) \\ \\ = > \frac{ - 18 + 20}{45} + \frac{ - 3}{4} = \frac{2}{5} + \frac{16 - 27}{36} \\ \\ = > \frac{ - 2}{45} + \frac{ - 3}{4} = \frac{2}{5} + \frac{ - 11}{36} \\ \\ = > \frac{ - 8 - 135}{180} = \frac{72 - 55}{180} \\ \\ = > - 143 = 17________________________________●SO.... WE KNOW THAT :-●"-143" is never equal to "17"●THEN=> -143 ≠ 17

___________________●GIVEN QUESTION :- = > ( \frac{ - 2}{5} + \frac{4}{9} ) + \frac{ - 3}{4} = \frac{2}{5} + ( \frac{4}{9} + \frac{ - 3}{4} ) \\ \\ = > ( \frac{( - 2) \times 9 + 4 \times 5}{45}) + \frac{ - 3}{4} = \frac{2}{5} + ( \frac{4 \times 4 + ( - 3) \times 9}{36} ) \\ \\ = > \frac{ - 18 + 20}{45} + \frac{ - 3}{4} = \frac{2}{5} + \frac{16 - 27}{36} \\ \\ = > \frac{ - 2}{45} + \frac{ - 3}{4} = \frac{2}{5} + \frac{ - 11}{36} \\ \\ = > \frac{ - 8 - 135}{180} = \frac{72 - 55}{180} \\ \\ = > - 143 = 17________________________________●SO.... WE KNOW THAT :-●"-143" is never equal to "17"●THEN=> -143 ≠ 17So

___________________●GIVEN QUESTION :- = > ( \frac{ - 2}{5} + \frac{4}{9} ) + \frac{ - 3}{4} = \frac{2}{5} + ( \frac{4}{9} + \frac{ - 3}{4} ) \\ \\ = > ( \frac{( - 2) \times 9 + 4 \times 5}{45}) + \frac{ - 3}{4} = \frac{2}{5} + ( \frac{4 \times 4 + ( - 3) \times 9}{36} ) \\ \\ = > \frac{ - 18 + 20}{45} + \frac{ - 3}{4} = \frac{2}{5} + \frac{16 - 27}{36} \\ \\ = > \frac{ - 2}{45} + \frac{ - 3}{4} = \frac{2}{5} + \frac{ - 11}{36} \\ \\ = > \frac{ - 8 - 135}{180} = \frac{72 - 55}{180} \\ \\ = > - 143 = 17________________________________●SO.... WE KNOW THAT :-●"-143" is never equal to "17"●THEN=> -143 ≠ 17So=> (-2/5 + 4/9) + (-3/4) ≠ 2/5 + (4/9 + -3/4)

Answered by sufi003
1

Answer:

(-2/5+4/5)+-3/4=-2/5+(4/9+(-3/4)

2/5-3/4 = -2/5 -(16/36-18/36)

8/20-12/20 = -2/5 +2/36

-4/20 = -72/180 + 10/180

-1/5 = -62/180

It is not equal

Step-by-step explanation:

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