Question

show that 2/√5 is a irrational no.

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Answer 1

Step-by-step explanation:

Given

2/√5 is irrational number,

By the method of contradiction,

let us assume that 2/√5 is 'Rational Number',

let,2/√5 = a/b where a & b are co-primes and b not = 0,

2/√5 = a/b

√5/2 = b/a

√5 = 2b/a

Here,

a & b are co-primes,

So,

2, √5, a, b are integers,

So,

√5 is rational number,

But it contradicts the fact that √5 is irrational number,

So, our assumption is wrong,

2/√5 is irrational number.

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