Question

show that 2 and -1/3 and zeroes of the polnomial 3^2-5x-2.​

Answer 1

Answer:

correct given quation :

p(x) = 3x^2 - 5x - 2

Step-by-step explanation:

put x = 2

p(2) = 3(2)^2 - 5(2) - 2 = 0

=> p(2) = 0

put x = -1/3

p(-1/3) = 3(-1/3)^2 - 5(-1/3)-2 =0

p(-1/3) = 0

since p(2) = 0 and p(-1/3) = 0 , therefore it is proved that 2 and -1/3 are the zeroes of Given polynomial .