show that 2 and -1/3 are the zeroes of polynomial 3x^3-2x^2-7x-2.
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Answer:
3x³-2x²-7x-2=0.
x=2.
3(2)³-2(2)²-7(2)-2=0.
3(8)-2(4)-14-2=0.
24-8-14-2=0.
10-8-2=0.
2-2=0.
0=0.
It is a zero polynomial.
x=-1/3.
3(-1/3)³-2(-1/3)²-7(-1/3)-2=0.
3(-1/27)-2(1/9)+7/3-2=0.
-1/9-2/9+7/3-2=0.
-9-18+21-2/9=0. (because LCM of 9, 9 & 3 is 9).
-9-18+19/9=0.
-9+1/9=0.
-8/9=0.
It is not in zero polynomial.
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