show that 2 and -1/3 are the zeroes of the polynomial 3x^2-5x-2
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Answer:
3x
2
+5x−2
=3x
2
+6x−x−2
=3x(x+2)−1(x+2)
=(3x−1)(x+2)
Hence the zeroes are
3x-1=0 x+2=0
x=⅓ x=-2
Solutions of 3x²+5x-2 are
(⅓,0) (-2,0) (1,6) (-1,-4)
Step-by-step explanation:
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