Show that 2 and -1/3 are the zeroes of the polynomial 3x^3-2x^2-7x-2. Also, find the third zero of the polynomial.
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-2
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1) p(x) = x3 + 2x2 - x -2
it means that (x+2) is a factor of p(x)
divide (x+2) by p(x)
you got x2 -1tep explanation:
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