Question

Show that 2 and -1/3 are the zeros of polynomial p (x) = 3x^2-5x-2.

Answer 1

Answer:

Step-by-step explanation:p[x]=2

3[2]^2-5[3]-2

12-15-2

-3-2

-5

p[x]=-1/3

3[1/3]^2-5[-1/3]-2

3[1/9]+5/3-2

1/3+5/3-2

lcm=3

[1+5-6]/3

0/3=0