Show that 2 and 3 are the zeros of the polynomial x³ - 3x² - 4x + 12. Also find the third zero of the polynomial.
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a−b,a,a+b are zeroes of x
3
−3x
2
+x+1
⇒a−b+a+a+b= sum of zeroes = 3
⇒3a=3
⇒a=1
(a−b)(a)(a+b)= product of zeroes =−1
⇒(1−b)(1+b)=−1
⇒1−b
2
=−1
⇒b
2
=2
⇒b=±
2
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