Math, asked by jacker69, 8 months ago

Show that 2 and - ⅓ are zeroes of the polynomial 3x² - 5x - 2​

Answers

Answered by Anonymous
48

Qᴜēsᴛíõñ :-

Show that 2 and - ⅓ are zeroes of the polynomial 3x² - 5x - 2

Söʟúᴛîøɴ :-

Given polynomial : p(x) = 3x³ - 5x - 2

p(2) = 3(2)² - 5(2) - 2

= 12 - 10 -2 = 12 - 12 = 0

p(-⅓) = 3(-⅓)² - 5(-⅓)-2

= ⅓ + 5/3 - 2

= 2 - 2 = 0

⛬ 2 and -⅓ are zeroes of p(x)

Answered by prajwal1697
0

\huge {\blue{ \boxed{ \boxed{ \pink{ \underline{ \underline{ \mathfrak{ \red{♡QueStioN♡}}}}}}}}}

Show that 2 and - ⅓ are zeroes of the polynomial 3x² - 5x - 2

_________________________

\huge {\blue{ \boxed{ \boxed{ \pink{ \underline{ \underline{ \mathfrak{ \red{♡AnSwεr♡}}}}}}}}}

3 {x}^{2}  - 5x - 2 = 0 \\  =  > 3 {x}^{2}  - 6x  + x - 2 = 0 \\  =  > 3x(x - 2) + 1(x - 2) = 0 \\  =  >( 3x  +  1)(x + 2) = 0 \\  =  >  \green{ \boxed{x = 2} }\\  =  >   \green{\boxed{x =  -  \frac{1}{3} }}

hope it helps you

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