Question

show that 2(cos^2 45=tan^2 60) -6 (sin^2 45 -tan^2 30 )=6

Answer 1

Hi ,

cos² 45 = 1/ 2

tan² 60 = 3

sin² 45 = 1/2

tan² 30 = 1/3

According to the problem given,

LHS = 2(cos² 45+ tan²60)-6(sin² 45-tan²30)

= 2 (1/2 + 3 ) - 6( 1/2 - 1/3)

= 1 + 6 - 3 + 2

= 9 - 3

= 6

= RHS

I hope this helps you.

:)