Question

Show that 2[cos²60°+sin4 30°]-[tan²60°+cot²45°]+3sec²30°=1/4​

Answer 1

Answer:

$2( \frac{1}{4} + \frac{1}{16} ) - (3 + 1) + 3 \times \frac{4}{3} = \\ 2 \times \frac{5}{16} - 4 + 4 = \\ \frac{5}{8}$

Answer 2

Step-by-step explanation:

I think RHS is incorrect.