Show that 2(cos4 60+sin4 30)-(tan2 60+cot4 45)+3sec2 30=1/4
ever 2 and 4 are square and cube
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Answer:
We need the following:
cos60=1/2=sin30
tan60=√3
cot45=tan45=1
sec30=1/√3
Returning to the question we have:
=> 2[(cos60)⁴ + (sin30)⁴] - [(tan60)² +
(cot45)⁴] + 3*(sec30)²
=> 2(1/16+1/16)-(3+1)+3*4/3
=> 1/4-4+4
=> 1/4
Proved !!
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