Question

Show that 2(cos4 60+sin4 30)-(tan2 60+cot4 45)+3sec2 30=1/4

ever 2 and 4 are square and cube

answer is urgent

Answer 1

Answer:

We need the following:

cos60=1/2=sin30

tan60=√3

cot45=tan45=1

sec30=1/√3

Returning to the question we have:

=> 2[(cos60)⁴ + (sin30)⁴] - [(tan60)² +

(cot45)⁴] + 3*(sec30)²

=> 2(1/16+1/16)-(3+1)+3*4/3

=> 1/4-4+4

=> 1/4

Proved !!

Answer 2

Step-by-step explanation:

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