Show that √2 is an irrational number
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Step-by-step explanation:
let √2 be a rational no.
√2 =p/q (where p and q are co prime no and q ≠0)
squaring on both side
2=p²/q²
2 * q² =p²
q²=p²/2... (1)
again let
p =2m
q²=2m²/2
q²/2=m²...(2)
from EQ (1) and (2)
2 is the common factor between p and q so our assumption is wrong as they are co prime no.
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