show that 2 is not a factor of polynomial x^2+7x+10
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Answered by
1
hey... Mate here's ur solution,
let,
the given equation be x² + 7x + 10
i. e ,
p ( x ) = x² + 7x + 10
Since,
p ( x ) = 0
therefore,
x² + 7x + 10 = 0
now put p ( x ) = 2
p ( 2 ) = ( 2 ) ² + 7 ( 2 ) + 10
p ( 2 ) = 4 + 14 + 10
= 28
Now,
28 ≠ 0
hence,
2 is not the factor of given equation.
hope it might be helpful !!
let,
the given equation be x² + 7x + 10
i. e ,
p ( x ) = x² + 7x + 10
Since,
p ( x ) = 0
therefore,
x² + 7x + 10 = 0
now put p ( x ) = 2
p ( 2 ) = ( 2 ) ² + 7 ( 2 ) + 10
p ( 2 ) = 4 + 14 + 10
= 28
Now,
28 ≠ 0
hence,
2 is not the factor of given equation.
hope it might be helpful !!
akshitakarn1326:
Thank you so much
Answered by
1
Hii....☺
Here is your solution.....☺
==================================
♦ To show 2 is not a factor of given polynomial.
In order to solve this question we just need to do is to put a value 2 in the place of x of the given polynomial.
=> x² + 7x + 10
=> 2² + 7*2+ 10
=> 4 + 14 + 10
=> 28
Hence, as a result we didn't obtained a value which is equal to 0.
Therefore, we can say that 2 is not the factor of the given polynomial.
=================================
Thanks...☺
Here is your solution.....☺
==================================
♦ To show 2 is not a factor of given polynomial.
In order to solve this question we just need to do is to put a value 2 in the place of x of the given polynomial.
=> x² + 7x + 10
=> 2² + 7*2+ 10
=> 4 + 14 + 10
=> 28
Hence, as a result we didn't obtained a value which is equal to 0.
Therefore, we can say that 2 is not the factor of the given polynomial.
=================================
Thanks...☺
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