Question

show that -2 is zero of 4x^3-5x^2-23x+6​

Answer 1

Step-by-step explanation:

•For -2 be the zeroes of the above equation the above equation should be equal to zero on putting-2 in place of x

•4x^3-5x^2-23x+6

•4×-2^3-5×-2^2-23×-2+6

•-32-20+46+6

•-52+52

•0

so, we can say that-2 is the zeroes of 4x^3-5x^2-23x

I hope that it may help!!!!