show that 2 log 5/8 + log 128/125 + log 5/2 =0
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Step-by-step explanation:
2 log 5/8 + log 128/125 + log 5/2
=log(5/8)^2 + log(5/2) + log(128/125)
from,
[a log(b)=log(b^a)]
=log(25/64) + log(5/2) - log(125/128)
from,
[log(a/b)=-log(b/a)]
=log(25×5/64×2) - log(125/128)
from,
[log(a) + log(b)=log(ab)]
=log(125/128)-log(125/128)
=0 (proved)
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