Math, asked by rroyyalanavyasri, 7 months ago

show that 2 log 5/8 + log 128/125 + log 5/2 =0​

Answers

Answered by rajeevr06
1

Answer:

2 log( \frac{5}{8} )  +  log( \frac{128}{125} )  +  log( \frac{5}{2} )  =

 log( \frac{25}{64} )  +  log( \frac{128}{125} )  +  log( \frac{5}{2} )  =

 log( \frac{25}{64}  \times  \frac{128}{125} \times  \frac{5}{2}  )  =  log(1)  = 0 \:  \: proved

Answered by swaraj2020
0

Answer:

same as above solution. nice work

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