Show that 2- root 2 is irrational number
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Let 2-√2 be rational.
Then, 2-√2 = p/q, where p and q are integers, q≠0, p and q are co-primes.
Squaring both sides,
(2-√2)² = (p/q)²
2² + (2√2)² - 2(2)(2√2) = p²/q²
4 + 8 - 8√2 = p²/q²
-8√2 = p²/q² - 4 - 8
-8√2 = p²/q² - 12 = (p² - 12)/(q²)
√2 = (p² - 12)/(q²)(-8) = (-p² + 12)/(8q²)
In the above equation, clearly LHS is an irrational value while RHS is a rational value. Thus, LHS ≠ RHS.
Thus, our supposition is wrong.
∴ 2 - √2 is irrational.
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