Math, asked by gs1463854, 10 months ago

show that (2+root3)(2- root 3)(5+root2 )(5-root2) is a rational number ​

Answers

Answered by super15
18

Answer:

(2 +  \sqrt{3} )(2 -  \sqrt{3} )(5 +  \sqrt{2} )(5 -  \sqrt{2} ) \\  =  > (2 {}^{2}  - ( \sqrt{3}  {)}^{2} )(5 {}^{2}  - ( \sqrt{2}  {}^{2} )) \\  =  > (4 - 3)(25 - 2) \\  =  > (1)(23) \\  =  > 23

Therefore, 23 is a rational number.

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