show that 2(x3-x)+3x(x-1)=x(x+1)(2x+1)
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2(x³-x)+3x(x-1)=x(x+1)(2x+1)
2x³-2x+3x²-3x=x(2x²+x+2x+1)
2x³+3x²-2x-3x=2x³+x²+2x²+x
2x³+3x²-5x=2x³+3x²+x
2x³-2x³+3x²-3x²-5x-x=0
-5x-x=0
-6x=0
x=0
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