Math, asked by mishikasood611, 1 year ago

Show that 21^n cannot end with digit 0,2,4,6,8 for any integer n

Answers

Answered by Bhagwan146
1
put value of n is 0,2,4,6,8, for any integer n than 21 never end with digit zero[0]
Answered by Letmedoit
0
21^1,21^2.... will never end with even numbers.two or more odd numbers always gives odd no.its a basic number system theorem
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