Question

Show that 25y^{2}+25y-36=0 .​

Answer 1

Answer:

PROVED

Step-by-step explanation:

GIVEN: $25y^{2} + 25y-36=0$

TO PROVE: $25y^{2} +25y-36=0$

SOLUTION:

$25y^{2}+25y-36=0$

USING SPLITTING THE MIDDLE TERM METHOD

25× 36 = 900

FACTORS OF 900 =( 20 and 45) will add up to make 25

so,

$25y^{2}+25y -36=0\\\\25y^{2} + 45y -20y -36=0\\\\ 5y(5y+9) -4(5y-9) =0\\\\(5y+9) (5y-4)=0\\\\EQUATING BOTH THE FACTOR WITH ZERO \\5y+9 =0\\y= \frac{-9}{5} ( negative values are rejected)\\5y-4=0\\y= \frac{4}{5}$

putting the value of y =$\frac{4}{5}$, in equation

$25y^{2} + 25y -36=0\\\\25 (\frac{4}{5}) ^{2} + 25(\frac{4}{5}) -36=0\\\\25 (\frac{16}{25}) +20 -36=0\\\\16+20-36=0\\\\36-36=0\\\\0=0$