show that 26 + √8 is irrational
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Step-by-step explanation:
let us assume to the contrary that 26+√8 is rational
thus 26+√8 =a/b
√8=a-26b/b
2√2 = a-26b /b (√8=2√2)
√2 = a-26b/2b
LHS √2 is irrational
and RHS a ,-26 , b are integers
thus LHS≠RHS
hence our assumption is wrong
thus 26+√8 is irrational
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