Show that 28 cannot end with digit 0 for any natural number
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It can be observed that 5 is not in the prime factorisation of (22x7)n or 28n. Hence, for any value of n, 28n will not be divisible by 5. Therefore, 28n cannot end with the digit 0 for any natural number
Answered by
0
Answer:
It can be observed that 5 is not in the prime factorisation of (22x7)n or 28n. Hence, for any value of n, 28n will not be divisible by 5. Therefore, 28n cannot end with the digit 0 for any natural number
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