Question

Show that 28^n cannot end with digit 0 for any natural number??​

Answer 1

Answer:

It can be observed that 5 is not in the prime factorisation of (22x7)n or 28n. Hence, for any value of n, 28n will not be divisible by 5. Therefore, 28n cannot end with the digit 0 for any natural number n

Answer 2

Step-by-step explanation:

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Refer to the above attachment ⬆️⬆️.