Question

show that 2and -⅓are zeroes of the polynomial px 3x²-5x-2​

Answer 1

P(x)= 3x^2-5x-2

P(2)= 3(2)^2-5(2)-2

= 12-10-2

= 12-12

=0

P(-1/3)= 3(-1/3)^2-5(-1/3)-2

= 3(1/9)+5/3-2

= 3/9+5/3-2

= 1/3+5/3-2

= 6/3-2

= 2-2

= 0

Therefore, 2 and -1/3 are zeroes of p(x).

Answer 2

Step-by-step explanation:

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