show that√2cos (45-A) = cas A sinA.
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root 2 cos(45-A)=cosA+sinA
By fundamental law,
root2(cos 45 cos A + sin 45 sinA)
root 2(1/root 2 cosA +1/root 2 sinA)
root2(1/root2)(cosA+ sinA)
cosA+ sinA
Answered by
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Answer:
multiplying and divide LHS √2
Step-by-step explanation:
√2 (1/√2 sin A + 1/√2 cos A)
and sin 45 = cos 45 = 1/√2
=> √2 (sin 45 sin A + cos 45 cos A)
=> √2 cos (45-A)
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