Show that 2cos20 - 1 = 1.- 2sin?O.
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Given pair of equations 2sin
2
θ−cos2θ=0 and 2cos
2
θ−3sinθ=0
2sin
2
θ−cos2θ=0
⇒2sin
2
θ−(1−2sin
2
θ)=0
⇒4sin
2
θ=1
⇒sinθ=±
2
1
And 2cos
2
θ−3sinθ=0
⇒2(1−sin
2
θ)−3sinθ=0
⇒2sin
2
θ+3sinθ−2=0
⇒sinθ=
4
−3±
9+16
⇒sinθ=
4
−3±5
⇒sinθ=
2
1
as−1≤sinθ≤1
So sinθ=
2
1
satisfies both the equations
⇒θ=
6
π
,
6
5π
as θ∈[0,2π]
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