Show that 2x+1 is a factor of polynomial 2x^3-11x^2-4x+1
Answers
Answered by
404
f(x) = 2x³-11x²-4x+1
If f(x) is divided by (2x+1), then f(-1/2) is the remainder.
f(-1/2) = 2(-1/2)³-11(-1/2)²-4(-1/2)+1
= 2(-1/8)-11(1/4)-4(-1/2)+1
= -1/4-11/4+2+1
= 3 - 12/4
= 3-3
= 0
(2x+1) is a factor of f(x) as remainder is zero.
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If f(x) is divided by (2x+1), then f(-1/2) is the remainder.
f(-1/2) = 2(-1/2)³-11(-1/2)²-4(-1/2)+1
= 2(-1/8)-11(1/4)-4(-1/2)+1
= -1/4-11/4+2+1
= 3 - 12/4
= 3-3
= 0
(2x+1) is a factor of f(x) as remainder is zero.
Hope it helps you ☺
Please mark as Brainliest ☺
Answered by
120
Hey there !!!!
If 2x+1=0 is a factor of p(x)=2x³-11x²-4x+1
then p(-1/2) =0
So,
p(x)=2x³-11x²-4x+1
p(-1/2) =2*(-1/2)³-11(-1/2)²-4*(-1/2)+1
= -2/8-11/4+2+1
= -1/4-11/4+3
=-12/4+3
=-3+3=0
Therefore 2x+1 is a factor of p(x)=2x³-11x²-4x+1.
Hope this helped you.....
If 2x+1=0 is a factor of p(x)=2x³-11x²-4x+1
then p(-1/2) =0
So,
p(x)=2x³-11x²-4x+1
p(-1/2) =2*(-1/2)³-11(-1/2)²-4*(-1/2)+1
= -2/8-11/4+2+1
= -1/4-11/4+3
=-12/4+3
=-3+3=0
Therefore 2x+1 is a factor of p(x)=2x³-11x²-4x+1.
Hope this helped you.....
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